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Physics 202
Tuesday, March 30, 1999
Announcements: None
Lecture notes:
Torque on a Current Loop in a Uniform
Magnetic Field
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We said the net force on a current loop in a constant magnetic field
is zero, but the torque is not necessarily zero!
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F = i (L (cross product) B)
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Case One
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Net Force = 0 Net Torque = 0
t = r (cross) F
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Case Two
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Net Force = 0 Net Torque
does not equal zero
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Define axis of rotation:
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through ED, then t = (a) (i) (b) B
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If Area of loop = A = ab, then t = (a) (i) (b)
B = i AB
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Through OF, t = (1/2)(a) (i) (b) B + (1/2)a
i b B = i AB
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Resolve B into 2 components
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Bsinq perpendicular to normal
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Bcosq along the normal (no torque)
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The component of B that's perpendicular to normal ( in the Bsinq
plane of the loop) gives the force
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F = i b Bsinq
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t = i b Bsinqa
= iABsinq = i(A (cross product) B)
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It is convenient to define a vector quantity for the area of the loop
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Area vector points along the normal of the loop
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To find direction use Right Hand Rule; Curl fingers in direction of i,
thumb points in direction of A
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We have shown that for a current flowing around a rectangular loop, into
a uniform B, the torque on the loop is
t = i(A (cross product)
B),
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It can be shown that the above relation is correct for current loop of
any shape.
Principles of Galvanometer
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t = i(A (cross product) B) = -Kq,
where K is the spring constant and q
is the angle of rotation
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The torque due to the current in the magnetic field is equal to the torque
of the restoring spring.
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Read about Magnetic Dipoles on your own\
Chapter 30; Sources of a Magnetic Field
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We learned that magnetic field can exert a force on a moving charge or
on a wire carrying a current.
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Moving charges or current are also sources of magnetic fields.
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Biot and Savart were the first to provide a quantitative description on
how a current produces an electric field.
Biot and Savart Law
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q is the angle between i ds and r
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r is the displacement vector from ds to point P ; r is the unit vector
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dB is the magnetic field at point P due to the current element i ds
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dB = (mo/4p)
( i ds (cross) r/ r2)
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(mo/4p)
= 10-7 Tm/A
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mo= permeability constant
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See example 30-1 on page 732 of the text.
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