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Physics 202

Tuesday, March 30, 1999
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Lecture notes:

 Torque on a Current Loop in a Uniform Magnetic Field
  •  We said the net force on a current loop in a constant magnetic field is zero, but the torque is not necessarily zero!
    • F = i (L (cross product) B)
    • Case One
      •  Net Force = 0      Net Torque = 0        t = r (cross) F
    • Case Two
      • Net Force = 0         Net Torque does not equal zero
    • Define axis of rotation:
      • through ED, then t = (a) (i) (b) B
        • If Area of loop = A = ab, then t = (a) (i) (b) B = i AB
      • Through OF,  t = (1/2)(a) (i) (b) B + (1/2)a i b B = i AB
  • Resolve B into 2 components
    • Bsinq perpendicular to normal
    • Bcosq along the normal (no torque)
    • The component of B that's perpendicular to normal ( in the Bsinq plane of the loop) gives the force
      • F = i b Bsinq
      • t = i b Bsinqa  = iABsinq = i(A (cross product) B)
    • It is convenient to define a vector quantity for the area of the loop
    • Area vector points along the normal of the loop
    • To find direction use Right Hand Rule; Curl fingers in direction of i, thumb points in direction of A
  • We have shown that for a current flowing around a rectangular loop, into a uniform B, the torque on the loop is              t = i(A (cross product) B),
  • It can be shown that the above relation is correct for current loop of any shape.

Principles of Galvanometer
  • t  = i(A (cross product) B) = -Kq, where K is the spring constant and q is the angle of rotation
  • The torque due to the current in the magnetic field is equal to the torque of the restoring spring.
  • Read about Magnetic Dipoles on your own\

Chapter 30; Sources of a Magnetic Field
  • We learned that magnetic field can exert a force on a moving charge or on a wire carrying a current.
  • Moving charges or current are also sources of magnetic fields.
  • Biot and Savart were the first to provide a quantitative description on how a current produces an electric field.

Biot and Savart Law

  • q is the angle between i ds and r
  • r is the displacement vector from ds to point P ; r is the unit vector
  • dB is the magnetic field at point P due to the current element i ds
    • dB = (mo/4p) ( i ds (cross) r/ r2)
    • (mo/4p) = 10-7 Tm/A
    • mo= permeability constant
    • See example 30-1 on page 732 of the text.

 
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